1372=16t^2

Solution for 1372=16t^2 equation:

1372=16t^2

We move all terms to the left:

1372-(16t^2)=0

a = -16; b = 0; c = +1372;
Δ = b2-4ac
Δ = 02-4·(-16)·1372
Δ = 87808
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{87808}=\sqrt{12544*7}=\sqrt{12544}*\sqrt{7}=112\sqrt{7}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-112\sqrt{7}}{2*-16}=\frac{0-112\sqrt{7}}{-32}
=-\frac{112\sqrt{7}}{-32}
=-\frac{7\sqrt{7}}{-2}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+112\sqrt{7}}{2*-16}=\frac{0+112\sqrt{7}}{-32}
=\frac{112\sqrt{7}}{-32}
=\frac{7\sqrt{7}}{-2}
$